Chem – College: Matchmaking Between Acidic and you may Ft Equilirium Constants (Ka and you may Kb)

Chem – College: Matchmaking Between Acidic and you may Ft Equilirium Constants (Ka and you may Kb)

When you are given multiple Ka or Kb values (like Ka step 1 , Ka dos , Ka step step three ), you can also combine them together into an overall Ka or Kb by multiplying them together. The equations below display what I mean.

If Mg(OH) 2 has a Kb 1 of 0.3 and a Kb 2 of cuatro.5 * 10 -3 what is the over all Kb value?

If Feel(OH)

If H 3 PO 4 has a Ka 1 of 2.8 * 10 -3 and a Ka 2 of 7.1 * 10 -6 . 3 if the overall Ka is 7.75 * 10 -17 ?

Answer: ( 2.8 * 10 -3 ) * ( 7.1 * 10 -6 ) * Ka 3 = 7.75 * 10 -17

If Al(OH) 3 has a Kb 1 of 0.04 and a Kb 2 of 5.1 * 10 -4 what is the over all Kb value?

If H 2 SO 4 has a Ka 1 of 15 and a Ka 2 of 2.0 * 10 -2 . Then what is the over all Ka value?

If H 3 PO 3 has Ka 2 of 4.7 * 10 -5 and a Ka 3 of 2.3 * 10 -8 . 1 if the overall Ka is 5.5 * 10 -16 ?

Answer: Ka1 * (4.7 * 10 -5 ) * (2.3 * 10 -8 ) = 5.5 * 10 -16 — Ka1 = 5.09 * 10 -4

2 has a Kb 1 of 3.6 * 10 -4 and an overall Kb of 8.2 * 10 -12 what would be the Kb 2 ?

Answer: (3.6 * 10 -4 ) * Kb 2 = 8.2 * 10 -12 — Kb 2 = 2.24 * 10 -8

It turns out one to Ka and you may Kb is related to you to various other during the a formula. It formula enables you to convert regarding Ka to Kb and vise versa. The brand new algorithm is actually revealed less than .

The great thing about that it algorithm would it be including gives you so you’re able to expect whether or not something is actually an acid otherwise a base . The way to contour if or not some thing are an acidic otherwise foot just by its Ka otherwise Kb well worth should be to evaluate it to your balance ongoing to possess drinking water as in the latest formula less than.

Should your Ka transforms planning to be a more impressive count than just the latest Kb then your chemical would be an acidic.

If the Kb converts going to feel a much bigger matter than just the new Ka then your chemical would-be a bottom.

Give the Kb and you may share with whether or not the chemical compounds is an acid otherwise ft when it has actually a great Ka regarding 2.cuatro * 10 -six .

Answer: Acidic (Ka is actually bigger than Kb), Kb = ten -14 / dos.cuatro * ten -six = 4.17 * 10 -9

Supply the Ka and you can tell whether or not the chemical substances is an acid or base if it features a great Kb of 3.5 * 10 -4 .

Answer: Ft (Kb is bigger than Ka), Ka = ten -fourteen / step 3.5 * ten -4 = dos.86 * ten -11

Supply the Kb and you can tell perhaps the chemical compounds is an acidic otherwise base if this possess a Ka off cuatro.step three * ten -9 .

Answer: Feet (Kb try bigger than Ka), Kb = 10 -fourteen / cuatro.3 * ten -nine = dos.32 * ten -six

Supply the Ka and you can share with if the chemical substances was an acid or legs if it has a good Kb from 8.9 * 10 -11 .

Answer: Acidic (Ka was larger than Kb), Ka = ten -fourteen / 8.nine * 10 -eleven = step 1.a dozen * 10 -4

Supply the Kb and you may give whether the chemical compounds try an acid https://datingranking.net/cs/sweet-pea-recenze/ or ft whether it features good Ka from seven.dos * ten -nine .

Answer: Base (Kb is actually bigger than Ka), Kb = ten -fourteen / 7.dos * ten -9 = 1.38 * ten -6

Allow the Ka and you can share with if the chemical substances are an acidic or feet whether or not it keeps a Kb out of cuatro.2 * 10 -twelve .

Answer: Acid (Ka was larger than Kb), Ka = 10 -14 / 4.2 * 10 -11 = 2.38 * ten -cuatro

Supply the Kb and you can tell whether or not the chemical substances is actually an acidic or ft if it features an effective Ka out of 3.4 * ten -step three .

Following what would end up being the Ka

Answer: Acid (Ka are larger than Kb), Kb = ten -fourteen / 3.4 * 10 -step three = dos.94 * 10 -several

Provide the Ka and share with whether or not the chemical substances are an acid or legs when it features an effective Kb of 5.six * 10 -7 .

Answer: Foot (Kb is actually larger than Ka), Ka = ten -fourteen / 5.6 * ten -seven = step one.78 * ten -8

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